Model 2 Simplification based on square & square root Practice Questions Answers Test with Solutions & More Shortcuts
simplification PRACTICE TEST [4 - EXERCISES]
Model 1 Simplification using VBODMAS
Model 2 Simplification based on square & square root
Model 3 Simplification based on cube & cube root
Model 4 Simplification with continued fraction
Question : 16
The square root of : ${(0.75)^3}/{1 - 0.75} + [0.75 + (0.75)^2 + 1]$ is :
a) 3
b) 2
c) 4
d) 1
Answer »Answer: (b)
Expression
= ${(0.75)^3 + (1 - 0.75)((0.75)^2 + 0.75 × 1 + {1}^2)}/{1 - 0.075}$
= ${(0.75)^3 + 1^3 - (0.75)^3}/{0.25}$
= $1/{0.25} = 100/25 = 4$
Required square root = $√{4} = 2$
Question : 17 [SSC CISF ASI 2010]
$√{1{1/4} × 64/125 × {1.44}}$ is equal to
a) $24/25$
b) $23/25$
c) 1$1/25$
d) $21/25$
Answer »Answer: (a)
Expression
= $√{5/4 × 64/125 × 1.44}$
= $√{16/25 × 144/100}$
= $4/5 × 12/10 = 24/25$
Question : 18 [SSC CGL Prelim 1999]
What is the square root of 0.09?
a) 0.03
b) 0.003
c) 0.3
d) 3.0
Answer »Answer: (c)
$√{0.09} = √{0.3 × 0.3} = 0.3$
Question : 19
The sum of $√{0.01} + √{0.81} + √{1.21} + √{0.0009}$ is :
a) 2.13
b) 2.03
c) 2.1
d) 2.11
Answer »Answer: (a)
$√{0.01} + √{0.81} + √{1.21} + √{0.0009}$
= 0.1 + 0.9 + 1.1 + 0.03 = 2.13
Question : 20 [SSC CGL Prelim 2004]
$√{{0.25}/{0.0009}} × √{{0.09}/{0.36}}$ is equal to :
a) 7$1/6$
b) 7$1/3$
c) $5/6$
d) 8$1/3$
Answer »Answer: (d)
Expression
= $√{{(0.25) × (0.09)}/{0.0009 × 0.36}}$
= $√{{25/100 × 9/100}/{9/10000 × 36/100}}$
=$√{{25 × 9 × 1000000}/{9 × 36 × 10000}}$
= ${5 × 10}/6 = 25/3 = 8{1}/3$
IMPORTANT quantitative aptitude EXERCISES
Model 2 Simplification based on square & square root Shortcuts »
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